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49x^2-49=0
a = 49; b = 0; c = -49;
Δ = b2-4ac
Δ = 02-4·49·(-49)
Δ = 9604
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9604}=98$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-98}{2*49}=\frac{-98}{98} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+98}{2*49}=\frac{98}{98} =1 $
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